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President Bush scheduled to appear in Martinsburg, W.Va.

June 29, 2007

President George Bush will be appearing in Martinsburg, W.Va. on Wednesday, July 4, according to the White House schedule released at midday Friday by the Associated Press in Washington, D.C.

"His appearance schedule shows that he will be in Martinsburg on July 4," said Natasha Metzler in the AP office.

While the schedule didn't specify the time or place, a Martinsburg radio station reported Friday morning that the president will be at an Independence Day holiday program at the West Virginia Air National Guard 167th Airlift Wing.

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